Basic InformationIt takes 6mol of electrons to convert 1mol of KCl to 1mol of KClO
36mol of electrons = 160.8091AH
1mol of KCl = 74.5513g
1mol of KClO
3 = 122.5495g
74.5513g of KCl will yield 122.5495g of KClO
3 (at 100% efficiency)
1g of KCl will yield 1.6438g of KClO
31g of KCl requires 2.1570AH to convert it to KClO
3Yield Calculations1)
Theoretical Yield [g] = Amount of KCl [g] x 1.6438It is desirable to leave a percentage of KCl in solution to help reduce anode wear and minimise KClO4 production.
2)
Theoretical Yield [g] = Amount of KCl [g] x (1 - KCl to leave [%]) x 1.6438The amount of KCl in the cell can be calculated using the cell volume and the solubility of KCl. I chose the solubility value at 20
oC (344g per L) for ease of creating the solution.
3)
Amount of KCl [g] = Cell Volume [mL] x 0.344Using 2 & 3
4)
Theoretical Yield [g] = Cell Volume [mL] x (1 - KCl to leave [%]) x 0.5655The actual yield will depend on efficiency of the cell which is affected by variables such as pH, temperature, and cell layout.
5)
Cell Yield [g] = Cell Volume [mL] x (1 - KCl to leave [%]) x Cell Efficiency [%] x 0.5655
So now that we know how much KClO
3 will be produced, how long will it take?
Run Time CalculationsIt takes 160.8091AH to convert 74.5513g of KCl or 2.1570AH per gram. I am going to switch to images for the equations to keep things neat.
6)

Incorporate cell efficiency and percent KCl to leave in solution
7)

Using 3 & 7
8 )

From VK2ZAY, average maximum cell amps is 2A/100mL. We do want to adjust this as different cell designs may tolerate more current, while others may need to be run “cooler”.
9)

Using 8 & 9
10)

Now we can use 5 and 10 as our starting equations

Next we well take in to account some recommendations...